Calculate the full and condensed electron configuration of Holmium (Ho).

Ho - Element 67

[Xe] 4f^{11} 6s^{2}

Aufbau Order | 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{10} 4p^{6} 5s^{2} 4d^{10} 5p^{6} 6s^{2} 4f^{11} |
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Expanded Form | 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{10} 4p^{6} 5s^{2} 4d^{10} 5p^{6} 4f^{11} 6s^{2} |

Largest Core | [Xe] |

Valence Subshells | 4f^{11} 6s^{2} Calculate Valence Electrons |

Number of Electrons | 67 |

Number of Unpaired Electrons | Coming Soon! |

Electrons Per Shell | 2, 8, 18, 29, 8, 2 |

Last Subshell | 6s2 |

Maximum Principal Quantum Number (n) | 6 |

Maximum Azimutal Quantum Numbers (l) | 1=s; 2=p; 3=d; 4=f; 5=p; 6=s |

Spin Occupations | Coming Soon! |

Magnetic Moment (Spin Only) | Coming Soon! |

Slater Screening Constant | Coming Soon! |