Valence Electrons in Lead (Pb)

Calculate the number of valence electrons in Lead using its electron configuration step by step.

Enter the atomic number or symbol of any element, and this calculator will calculate its valence electrons with steps.

Valence Electrons in Lead

Determine the number of valence electrons in Lead (Pb, Element 82)

Step 1: Look up the electronic configuration for Lead

The abbreviated (condensed) ground electronic configuration for Lead is:

[Xe] 4f14 5d10 6s2 6p2

Calculate Electronic Configuration for Lead

Step 2: Identify the outermost electrons using the electronic configuration

Electrons in atomic orbitals outside the [Xe] core are the outermost electrons:

4f14 5d10 6s2 6p2

Step 3: Use the principle quantum number to identify the valence electrons

Extract the principle quantum number, n, and number of electrons from the electron configuration:

Electron ConfigurationnOrbitalNumber of Electrons
4f144f14
5d105d10
6s26s2
6p26p2

The outermost electrons with the largest principal quantum number (in this case, n = 6) are valence electrons.

Answer

Lead (Pb) has 4 (2 + 2) valence electrons.

Lewis Dot for Pb